Electrical · Calculator

Voltage divider.

Two-resistor voltage divider — output voltage, current draw, and power dissipation in each resistor. Plus the closest E12 and E24 standard resistor values.

How the math works

Vout = Vin × R2 / (R1 + R2)

Current  I = Vin / (R1 + R2)
Power R1   P1 = I² × R1
Power R2   P2 = I² × R2

The formula assumes no load on the output — i.e., the downstream circuit draws negligible current compared to what flows through the divider. If the load draws current comparable to I, the actual Vout will sag (it forms a Thévenin source with output impedance R1∥R2).

Rule of thumb: load resistance ≫ R1∥R2

For the voltage divider to work as designed, the load resistance should be at least 10× higher than the parallel combination of R1 and R2. If your load is 10 kΩ, your divider's R1∥R2 should be ≤ 1 kΩ.

This trades off against power dissipation: lower R values mean more current flows continuously, which means more wasted power and more heat. The classic compromise is to make R1+R2 around 10-50× the load impedance.

Common pitfalls

Sources

Disclaimer. Voltage dividers are appropriate for level-shifting and sensing applications. For power delivery, use a voltage regulator (LDO, switching regulator) instead.

See also